Explain when 0.89 g zncl2 is dissolved and nacn

Reference no: EM13514337

When 0.89 g ZnCl2 is dissolved in 280. mL of 0.150 M NaCN, what are [Zn2+], [Zn(CN)42- ], and [CN- ] [Kf of Zn(CN)42- = 4.2 multiplied by 1019]?

1.[Zn2+]

2. [Zn(CN)42-]

3.[CN -]

Reference no: EM13514337

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