Explain what was the ka for the unknown acid

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Reference no: EM13261286

A 0.146 g sample of an unknown monoprotic acid (molar mass = 83.0 g/mol) was dissolved in 50.0 mL of water and titrated with a 0.101 M NaOH solution. After the addition of 14.0 mL of base, the pH was 5.12. What was the Ka for the unknown acid?

Reference no: EM13261286

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Explain what was the ka for the unknown acid : A 0.146 g sample of an unknown monoprotic acid (molar mass = 83.0 g/mol) was dissolved in 50.0 mL of water and titrated with a 0.101 M NaOH solution. After the addition of 14.0 mL of base, the pH was 5.12. What was the Ka for the unknown acid

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