Explain what is the rate constant, of the 27.0

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Question - A certain reaction has an activation energy of 67.0kJ/mol and a frequency factor of A1 = 4.50*10^12 M-1s-1. What is the rate constant, of the 27.0?

K=A1 e^(-Ea/RT)
k=(4.50*10^12)e^(67000(8.314*300))=2.086 M-1 s-1 what I have got but mastering chemistry is not accepting my answer and I don't know where I am making mistake. Need help and please do show the calculations.

I want you to explicate the chemistry in this problem

Reference no: EM13717159

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