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What is the pKa for the pyridium cation? Pyridine + H2O <----> Pyridium cation + OH- Kb = 1.71 *10^-9 A. pKa for the pyridium cation = 3.9 B. pKa for the pyridium cation = 5.2 C. pKa for the pyridium cation = 7.4 D. pKa for the pyridium cation = 8.8 E. pKa for the pyridium cation = 10.1
One approach to the synthesis of virstatin is shown above. An SN2 reaction of an anionic imide nucleophile (formed by deprotonation of1) with an alkyl halide electrophile 2 affords virstatin ethyl ester 3 Base-inducedhydrolysis
Draw the structure(s) of the aldehydes with the molecular formula C5H10O that have a three-carbon chain.
Measurements also show that a certain sample of the unknown compound contains 9.8 mol of oxygen and 3.31 mol of chromium.
Plutonium-239 is a byproduct of the fission reaction used to produce energy in nuclear power reactors. It has a half-life of 24,400 years. A student determines that it will take 97,600 years for the radioactivity of a Pu-239 sample to drop to one-..
Draw the LUMO Huckel MO for the cation 1, 3, 5-heptatriene (carbocation is carbon 7). Also, please state the number of pi electrons in this conjugate system
Calculate the number of moles of HCl in the solution dispensed and its associated error.
nbspa solution of 6.05 m of an acid hx has a density 0.892 gml. molar mass of the acid hx 2.00 gmol. find out the
Could you explain why carbonate, specifically sodium carbonate (Na2CO3) would be particularly good at neutralizing these acids and their conjugate bases?
Protein Quantification How did you determine whether your spectrophotometer was accurate(see hint above) and if it was not,what is the error?
If the Km of the above enzyme is 12 mM, calculate the substrate concentration needed to achieve 40% of maximal velocity. Then what fraction of active sites are filled at 40% maximal velocity
a box contains 126000 red marbles and 885000 yelllow marbles. What sample size is required to reduce the sampling standard deviation of red marbles to 1.85%
Calculate Kc for the following reaction. 2NO(g)+O2(g) 2NO2(g) when equilibrium is established at 500 Kelvin, there are 0.190 moles of NO2, 2.65*10^-4 moles NO, and 0.606 moles O2 in a volume of 0.759 liters
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