Explain what is the ph of the resulting buffer

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500.0 mL of 0.120 M NaOH is added to 575 mL of 0.200 M weak acid (Ka = 3.84 × 10-5). What is the pH of the resulting buffer? HA(aq) + OH^-(aq) ---> H20(l) + A^- (aq) pH=

Reference no: EM13325057

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Explain what is the ph of the resulting buffer : 500.0 mL of 0.120 M NaOH is added to 575 mL of 0.200 M weak acid (Ka = 3.84 × 10-5). What is the pH of the resulting buffer. HA(aq) + OH^-(aq) ---> H20(l) + A^- (aq) pH=

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