Explain what is the percent yield of barium iodate

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A student synthesized 6.895 g of barium iodate monohydrate, Ba(IO3)2.H20 by adding 30.00 ml of 5.912x10^-1 M barium nitrate Ba(NO3)2 to 50.00ml of 9.004 x10^-1 M sodium iodate,NaIO3.

What is the percent yield of barium iodate monohydrate obtained in the experiment

Reference no: EM13651467

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