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Question- 1.) If your Aspirin sample did not dry completely and contained water in the sample would it require more or less NaOH solution to reach the endpoint of the titration?
2.) The concentration of NaOH on the bottle reads 0.0751 M. The concentration is actually 0.1023M. Will the value you compute for percent purity of Aspirin sample be too high, too low, orunchanged? Explain
3.) A 0.421 g sample of aspirin prepared in the laboratory is dissolved in 95% ethanol, diluted with water, and titrated to a phenolphthalein endpoint with 17.3 mL of 0.114 M NaOH. What is the percent purity of aspirin in the sample?
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you are asked to titrate a 6.00 ml sample of vinegar using 0.25m naoh. the mass of your vinegar sample was 6.168g so
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