Explain what is the percent of ethanol in the vodka

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a 25 mL solution contains 0.244 M of Cr^3+. 2.5mL of a diluted concentration of vodka was used in the 25mL solution, (vodka is diluted by (1/40) of it's original), what is the percent of ethanol in the vodka, based on the concentraion od Cr^3+. PLEASE I AM so stuck! HELP this is the formula used 16H^+ + 3CH2CH2OH + 2Cr2O7^2- = 3CH3CO2H + 4Cr^3+ + 11H2O. The only thing you need to use from the equation is the mole ratio of ethanol to chromium (which is 3/4)

Reference no: EM13335307

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