Explain what is the equivalent weight of mno4

Reference no: EM13238675

you take an unknown solution and measure 1ML of it into a flask. You dilute it with 25mL of water and 10mL of H2SO4. You titrate the solution with 19.80 mL of KMnO4. The (MnO4)- is reduced to (Mn) 2+ by the unknown solution.

a) What is the equivalent weight of (MnO4)- for the experiment?

b) How many equivalents of electrons were delivered to the unknown soln?

c) What is the normality of the unknown solution?

d) if 2 moles of electrons are required to oxidize 1 mole of unknown, what is the molarity of the unknown soln?

e) what piece of data is necessary to calculate the unknown's equivalent weight?

Reference no: EM13238675

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