Explain what is the equivalent mass of the unknown acid

Reference no: EM13164147

The student dissolved 2.570 grams of acid in 50 mL of distilled water. He then titrated the unknown acid with a standardized NaOH solution. Unfortunately, the student over shot the end point and had to back titrate the solution with 3.50 mL of 0.99897 M HCl. Once the final end point was determined, the student has added a total of 33.55 mL of a 1.0446 M NaOH solution. How many moles of OH were used to reach the end point? How many moles of H from HCl were used for back titration? How many moles of H from the solid were neutralized? What is the equivalent mass of the unknown acid?

Reference no: EM13164147

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