Explain what is the equalibrium concentration of pcl5(g)

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For the equalibrium PCl5(g) <--> PCl3(g) + Cl2(g), Kc= 2.0 x 10^1 at240 celcius. If pure PCl5 is placed in a 1.00-l container and allowed to come to equalibrium, and the equalibrium concentration of PCl3(g) is 0.23 M, what is the equalibrium concentration of PCl5(g)?

Reference no: EM13504519

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Explain what is the equalibrium concentration of pcl5(g) : For the equalibrium PCl5(g) PCl3(g) + Cl2(g), Kc= 2.0 x 10^1 at240 celcius. If pure PCl5 is placed in a 1.00-l container and allowed to come to equalibrium, and the equalibrium concentration of PCl3(g) is 0.23 M, what is the equalibrium concentr..

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