Explain what is ds of the universe

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Reference no: EM13662669

Suppose one mole of superheated water is evaporated at 383 K and 101 kPa. Compute DS of the water and of the surroundings, DHv(373 K) = 47.3 kJ mol-1, Cp(H2O,l) = 75.4 J K-1 mol-1, and Cp(H2O,g) = 30.36 + 9.61x10-3T + 11.8x10-7T2 (J K-1 mol-1). Explain what is DS of the universe?

Reference no: EM13662669

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Explain what is ds of the universe : Suppose one mole of superheated water is evaporated at 383 K and 101 kPa. Compute DS of the water and of the surroundings, DHv(373 K) = 47.3 kJ mol-1, Cp(H2O,l) = 75.4 J K-1 mol-1, and Cp(H2O,g) = 30.36 + 9.61x10-3T + 11.8x10-7T2 (J K-1 mol-1). Ex..

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