Explain what are the equilibrium partial pressures of ibr

Reference no: EM13270790

At 1478 oC the equilibrium constant for the reaction: 2 IBr(g) ? I2(g) + Br2(g) is KP = 0.899. If the initial pressure of IBr is 0.00169 atm, what are the equilibrium partial pressures of IBr, I2, and Br2? p(IBr) = . p(I2) = . p(Br2) = .

Reference no: EM13270790

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Explain what are the equilibrium partial pressures of ibr : At 1478 oC the equilibrium constant for the reaction: 2 IBr(g) ? I2(g) + Br2(g) is KP = 0.899. If the initial pressure of IBr is 0.00169 atm, what are the equilibrium partial pressures of IBr, I2, and Br2? p(IBr) = . p(I2) = . p(Br2) = .

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