Explain titration of the excess unreacted edta

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A 50.0 mL sample containing Cd2 and Mn2 was treated with 43.0 mL of 0.0400 M EDTA. Titration of the excess unreacted EDTA required 11.6 mL of 0.0200 M Ca2 . The Cd2 was displaced from EDTA by the addition of an excess of CN-. Titration of the newly freed EDTA required 11.2 mL of 0.0200 M Ca2 . What were the molarities of Cd2 and Mn2 in the original solution?

Reference no: EM13195654

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