Explain the vmax of the enzyme when enzyme concentration

Reference no: EM13517861

An enzyme (MW = 20,250) catalyzes the hydrolysis of a newly discovered substrate. The kcat was found to be 2000 sec-1 and Km = 0.05 M. Using this information answer the following questions.

a) What is the Vmax of this enzyme when enzyme concentration equal to 0.3 mg ml-1? b) When the above reaction was carried out in the presence of 2.5 ?M inhibitor, the Vmax is 0.03 M sec-1. What kind of inhibitor is this? Justify your answer with proper explanation.

Reference no: EM13517861

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