Explain the vaporization process is equal to 8.70 kj

Reference no: EM13487145

When 3.00 mol of benzene is vaporized at a constant pressure of 1.00 atm and at its normal boiling point of 80.1°C, 101.8 kJ are absorbed and P?V for the vaporization process is equal to 8.70 kJ then

Reference no: EM13487145

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Explain the vaporization process is equal to 8.70 kj : When 3.00 mol of benzene is vaporized at a constant pressure of 1.00 atm and at its normal boiling point of 80.1°C, 101.8 kJ are absorbed and P?V for the vaporization process is equal to 8.70 kJ then

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