Explain the turnover number for an enzyme

Reference no: EM13162419

The turnover number for an enzyme is known to be 5,000 min-1. From the following set of data, calculate the Km and the total amount of enzyme present in these experiments. Substrate concentration (mM) 1 2 4 6 100 1,000 Initial velocity (µmol/min) 167 250 334 376 498 499 (a) Km = about 2mM. (b) Total enzyme = 0.1 µmol.

Reference no: EM13162419

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