Explain the titrant twice as concentrated in hydroxide ion

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Reference no: EM13231052

Could someone please explain how to get the values in the table listed below? Any help would be greatly appreciated!

Consider a different titrant for this exercise. Suppose Ca(OH)2 were used as the titrant, instead of NaOH. This will make the titrant twice as concentrated in hydroxide ion. The analyte will still be HC2H3O2.

concentration of Ca(OH)2 0.327 M
volume vinegar solution 12.04 mL
mass vinegar solution 12.10 g
volume of Ca(OH)2 solution 13.95 mL

a. mmol of Ca(OH)2 = _____ mmol

b. mmol of HC2H3O2 = _____ mmol

c. mass of HC2H3O2 = _____ g

d. mass % of HC2H3O2 in the original sample = _____ %

e. molarity of HC2H3O2 in the original sample = ______ M

Reference no: EM13231052

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