Explain the stoiometry between oxalic acid and naoh

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Reference no: EM13287452

if I have .42N NaOH and the stoiometry between Oxalic acid and Naoh is 1:2 then does that mean i do .42/.5=mol Oxalic acid * vol of titrations = molarity of oxalic acid?

or would it just be .5mol oxalic acid *vol titrations = molarity of oxalic acid

Reference no: EM13287452

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