Explain the resulting ph when 0.005 moles of koh

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What is the resulting pH when 0.005 moles of KOH is added to 0.100 L of a buffer solution that is 0.100 M in H2PO4 - and 0.100 M HPO4 2- and the Ka2 = 6.2 x 10^-8?

Reference no: EM13500078

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