Explain the reduction potentials for mn2

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A voltaic cell consists of an Mn/Mn2+ half-cell and a Pb/Pb2+ half-cell. Calculate Ecell when [Pb2+] = 0.616 M and [Mn2+] = 1.069 M. You should use the reduction potentials for Mn2+ is -1.18 V and for Pb2+ is -0.125 V.

Reference no: EM13493096

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Explain the reduction potentials for mn2 : A voltaic cell consists of an Mn/Mn2+ half-cell and a Pb/Pb2+ half-cell. Calculate Ecell when [Pb2+] = 0.616 M and [Mn2+] = 1.069 M. You should use the reduction potentials for Mn2+ is -1.18 V and for Pb2+ is -0.125 V.
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