Explain the reaction takes place in a bomb calorimeter

Reference no: EM13232828

When 2.50g of glucose (C6H12O6) burns in air, carbon dioxide gas and liquid water are formed. 38.9kJ of heat are also liberated.
1. What is the heat flow of the reaction if 85.0 g of glucose are burned?
For this I just did 38.9/2.5 g *18.5g and got -1322.6 kJ. Is this the correct way of doing this part.

2. The reaction takes place in a bomb calorimeter where 4.50g of glucose are burned. What is the heat capacity of the bomb if the temp. of the water in the bomb increases from 22.75 degrees Celsius to 25.32 degrees Celsius? I used qrxn = -Ccal*change in time for this but am not sure if that is the right equation to use.

3. Using the heat capacity of the bomb calculated in the last part what would the temp. change of the water in the bomb be if 12.0g of glucose were burned?

4. How many grams of glucose must be burned to liberate ten kJ of heat?

Reference no: EM13232828

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