Explain the percent yield for the reaction of 3na2s

Reference no: EM13292587

How many mL of .200 M FeCl3 are needed to react with an excess of Na2S to produce 2.75 g of Fe2S3 if the percent yield for the reaction is 65%? 3Na2S + 2FeCl3 = Fe2S3 + 6NaCl

a) 50.9 mL

b) 86.0 mL

c) 102 mL

d) 203 mL

Reference no: EM13292587

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