Explain the percent ionization of niacin

Reference no: EM13497221

The percent ionization of niacin (C6H5NO2), (whose Ka is 1.5 x 10^-5) in a .020 M solution is 2.7%. Calculate the percentage of niacin molecules ionized in a solution that is (a) 0.010 M (b) 1.0 x 10^-3 M

Reference no: EM13497221

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