Explain the original molarity of a solution of formic acid

Reference no: EM13319477

The original molarity of a solution of formic acid (HCOOH) with a Ka= 1.7*10^-4 whose pH is 4.52 at equilibrium is: A. 8.52 *10^-9 B. 2.24*10^-4 C. 6.78*10^-3 D. 3.54*10^-5 E. 5.32*10^-7

Reference no: EM13319477

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