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Problem- Based on the molecular structures of the fluorocarbons, account for the difference in their solubilities.
CF4= 1.66 x 10^-3m
CCIF3= 8.45 x 10^-4m
CCl2F2= 2.27 x 10^-3m
CHClF2= .0338m
I need proficient help to solve the above problem
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