Explain the lead iodide dissolves according to the reaction

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Assume that a student places 1.0 mol of solid PbI2 in 1.0 L of water. Part of the lead iodide dissolves according to the following reaction PbI2(s) Pb2+ (aq) + 2I-(aq) After allowing the solution to sit for 30 minutes the student determines that the iodide concentration was [I-] = 0.0032 M. What is the Pb2+ concentration?

Reference no: EM13500399

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Explain the lead iodide dissolves according to the reaction : Assume that a student places 1.0 mol of solid PbI2 in 1.0 L of water. Part of the lead iodide dissolves according to the following reaction PbI2(s) Pb2+ (aq) + 2I-(aq) After allowing the solution to sit for 30 minutes the student determines that th..
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