Explain the equilibrium partial pressures for the reaction

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Reference no: EM13697162

Problem- At 25 °C, the equilibrium partial pressures for the following reaction were found to be PA = 5.10 atm, PB = 1.80 atm, PC = 8.10 atm, and PD = 7.40 atm.

A(g) + 2B(g) -> 4C(g) + D(g)

What is the standard change in Gibbs free energy of this reaction at 25 °C.

Delta G rnx = ?KJ/mol

Show all work, use additional paper if necessary.

Reference no: EM13697162

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