Explain the cd2+ concentration at the equivalence point

Reference no: EM13535976

A 50.00mL solution of 0.100M Cd2+ is titrated with 0.100M EDTA buffered at a pH of 7.2. What is the Cd2+ concentration at the equivalence point? Kf CdY2-= 2.9e16, Ka1 EDTA= 1.02e-2, Ka2 EDTA= 2.14e-3, Ka3 EDTA= 6.92e-7, Ka4 EDTA= 5.5e-11

Reference no: EM13535976

Questions Cloud

Calculate how far does the skier glide : A skier starts from rest at the top of a hill that is inclined at 9.3° with respect to the horizontal. How far does the skier glide along the horizontal portion of the snow before coming to rest

Define the empirical formula of the co2 compound : A 0.4168-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in oxygen to yield 0.7745 g of CO2 and 0.1586 g of H2O. What is the empirical formula of the compound?

What is the force acting on the person feet : If a 100 kilogram person was standing in the elevator and it accelerated downward at 3 m/s^2. What is the force acting on the person feet

Function of pyrenoids : Why are yeast included amongst multicellular decomposer though they have a unicellular body? Function of pyrenoids

Explain the cd2+ concentration at the equivalence point : A 50.00mL solution of 0.100M Cd2+ is titrated with 0.100M EDTA buffered at a pH of 7.2. What is the Cd2+ concentration at the equivalence point. Kf CdY2-= 2.9e16, Ka1 EDTA= 1.02e-2, Ka2 EDTA= 2.14e-3, Ka3 EDTA= 6.92e-7, Ka4 EDTA= 5.5e-11

Calculate patient revenue on accrual basis : Calculate patient revenue on accrual basis for the coming year. Subdivide revenue by program, and within each program subdivide it by type of payer.

Compute the magnitude of the tension in the monkeys arm : A 12.3-kg monkey is hanging by one arm from a branch and swinging on a vertical circle. compute the magnitude of the tension in the monkey's arm

Explain carbon dioxide moves from cells to the air in lungs : Using the concepts of equilibrium and Le Chatelier's principle, explain why oxygen moves from the air in the lungs to cells and carbon dioxide moves from cells to the air in the lungs.

Find the force exerted by the lower string on lower block : Two block each of 3.0 kg are held by strings. The upper string exerts a force F of 100 Newtons. find the force exerted by the lower string on the lower block

User Account

All Pages