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The atmospheric oxidation of nitrogen monoxide, 2 NO(g) +O2(g) 2NO2(g), was studied at some temperature withinitial pressures of 1.000 atm of NO and 1.000 atm ofO2. A tequilibrium PO2=.506 atm calculate Kp 2NO(g)+O2(g) 2NO2(g)
For H3PO3, Ka1 = 1.0x10- 2and Ka2 = 2.6x10-7. Calculate a value for the [H2PO3] in a 0.500 molar solution of H3PO3
The minimum frequency of light needed to eject electrons from a metal is called the threshold and find the minimum energy needed to eject electrons from a metal with a threshold frequency of 3.27*10^14s^-1.
A solution is prepared by adding 1.10 g of solid rm NaCl to 50.0 mL of 0.100 M {CaCl_2}. What is the molarity of chloride ion in the final solution? Assume that the volume of the final solution is 50.0 mL.
What is the concentration of Co2 ions at equilibrium? Assume the formation constant of Co(NH3)62 is 5.0× 1031.
Organic Chem: A hexose A was obtained after (-) glyceraldehyde underwent three successive Killani-Fischer syntheses. Oxidation of A with nitric acid forms an optically inactive aldaric acid B. Wohl degradation of A followed by nitric oxidation giv..
306 mL of a .208 M solution of silver nitrate will react with 146mL of a .170 M solution of sodium phosphate to produce how many grams of silver phosphate precipitate?
method would be a quick way to detect the presence of bromine/chlorine?
What is the specific heat capacity (in SI unit) of the following.
Why is this important and if this step was not done, how could this change your results (in other words what specifically would happen to the Ksp value?
How many grams of formic acid, HCOOH, must be added to 0.210 L of 0.160 M sodium formate, HCOONa, to yield a buffer solution with a pH of 4.10? Assume no volume change. Ka of HCOOH = 5.0 10-4.
what is the theoretical yield of carbon dioxide when 56.0 g of methane is burned in a excess of oxygen, according to the equation CH4 2 )2 ->CO2 ,2H2o.
Two different proteins X and Y are dissolved in aqueous solution at 37 C. The proteins bind in a 1:1 ratio to form XY. A solution that is initially 1.00 mM in each protein is allowed to reach equilibrium. At equilibrium, 0.18 mM of free X and 0.18..
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