Explain taking the polarity of the carbonyl group

Reference no: EM13151278

how to explain this question?
From: 15.31Cyclopropanone is highly reactive because of its large amount of angle strain. but methylcyclopropenone, although even more strained than cyclopro-panone, is nevertheless quite stable and can even be distilled. Explain, taking the polarity of the carbonyl group into account.

Reference no: EM13151278

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