Explain stomach acid

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A student is given an antacid tablet that weighed 5.6832g. The tablet was crushed and 4.3628 g of the antacid was added to 200mL of simulated "stomach acid". This was allowed to react and then filtered.

It was found that 25mL of this partially neutralized stomach acid required 8.5mL of a NaOH solution to titrate it to a methyl red endpoint.

If it took 21.5mL of this NaOH solution to neutralize 25mL of this NaOH solution to neutralize 25mL of the original acid:

A) How much of the "stomach acid" had been neutralized in the 25mL sample which was titrated?

B) How much stomach acid was neutralized by the 4.3628 g tablet?

C) How much stomach acid would have neutralized by the original 5.6831 tablet?

Reference no: EM13238269

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