Explain saturated affect the calculated value of the ksp

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If a solution of Ca(OH)2 (before the titration, Ca(OH)2 (aq) was prepared) wasn't truely saturated (it was unsaturated) how would this affect the calculated value of the Ksp?

Reference no: EM13213181

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Explain saturated affect the calculated value of the ksp : Ca(OH)2 (aq) was prepared) wasn't truely saturated (it was unsaturated) how would this affect the calculated value of the Ksp?
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