Explain reduction potential values of mn2

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A voltaic cell consists of an Mn/Mn2+ half-cell and a Pb/Pb2+ half-cell. Calculate [Pb2+] when Ecell is 1.017 V and [Mn2+] = 0.589 M. Use reduction potential values of Mn2+ = -1.18 V and for Pb2+ = -0.13 V.

Reference no: EM13493148

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