Explain naoh was required to back titrate the excess hcl

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The mixing of barium chloride solution with sodium carbonate solution resulted in a white precipitate. 25.00 ml of 0.3000 M HCl was added to 0.250 g of the solid with resultant fizzing and dissolving of the sample. 24.80 ml of 0.2000 M NaOH was required to back titrate the excess HCl. What was the calculated molecular mass of the product and how likely is it that the product was barium carbonate?

Reference no: EM13650291

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