Explain multiply this new k value for reaction

Reference no: EM13490953

Am i doing this correctly?? I am trying to find the standard reduction potential for the following reaction: 1). ClO3^- + 6H^+ + 6e^- -----> Cl^- + 3H2O given this information below: 2). ClO3^- + 6H^+ + 5e^- ----> (1/2)Cl2 (g) + 3H2O standard reduction potential= 1.458 V 3). Cl2 (g) + 2e^- ------> 2Cl^- standard reduction potential= 1.360 V Am i assuming correctly if i convert the E standard numbers for reactions 2 and 3 above into K (equilibrium constants) values, divide the K value for reaction 3 by 2 since you only need (1/2) Cl2 + e^- ------> Cl^- , then multiply this new K value for reaction 3 by the k value for reaction 2 to "add" the k values together in order to determine the K value of reaction 1.. From the K value of reaction 1, i converted it to E standard. would this be the correct way to approach this problem

Reference no: EM13490953

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Explain multiply this new k value for reaction : multiply this new K value for reaction 3 by the k value for reaction 2 to "add" the k values together in order to determine the K value of reaction 1.. From the K value of reaction 1, i converted it to E standard. would this be the correct way to ..

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