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Explain methyl alcohol in an abundant excess of oxygen

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The combustion of methyl alcohol in an abundant excess of oxygen follows the equation 2CH3OH+3O2 = 2CO2+4H2O. When 7.65g of CH3OH was mixed with 12.5g of O2 and ignited 6.96g of CO2 was obtained. What was the percentage yield?

Reference no: EM13560175

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