Explain ionized using a photon of ultraviolet radiation

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The first ionization energy of lead (Pb) is 716 kJ/mol. If a Pb atom is ionized using a photon of ultraviolet radiation having an energy of 1.987E-18 J, what is the amount of leftover energy that goes into the kinetic energy of the ejected electron?

Reference no: EM13553845

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Explain ionized using a photon of ultraviolet radiation : The first ionization energy of lead (Pb) is 716 kJ/mol. If a Pb atom is ionized using a photon of ultraviolet radiation having an energy of 1.987E-18 J, what is the amount of leftover energy that goes into the kinetic energy of the ejected electro..
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