Explain how many mole of aluminum are needed to react

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The reaction of aluminum with hydrocholoric acid can be shown as follows : 2AI(s) + 6 HCI(aq) --> 2AICI3(aq) + 3H2(g). How many mole of aluminum are needed to react with 1.16 mol of hyrocholoric acid?

Reference no: EM13558985

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