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A ballon is filled with H2 gas and has a pressure of 1.10 atm, volume of 10.2L, and a temp of 298 K. How many grams of H2 gas are in the sample?
How can one draw a best fit straight line on a temperature versus time graph to determine the temperature at which two phases (solid plus melting point) appear
the enthalpy change for melting ice at 0degc and constant atmospheric pressure is 6.01 kjmol. calculate the quantity of
Write the structures (or name the structures) for the major monobromination products that would be formed from each of the following substrates used. Explain your predictions.
List possible manipulation errors that might contribute to the following errors in results
A solution is prepared by adding 50.0 ml of 0.050M HBr to 150.0 ml of 0.10M HI. Calculate the concentration of all species in this solution. HBr and HI are both considered strong acids.
c2h4g o2g co2g h2oghow many moles of o2 would be required to react with 0.640 moles of c2h4 in the above unbalanced
A sample of nitrous oxide gas, N2O in a nonrigid container at a temperature of 33C occupies a certain volume at a certain pressure. What will be its temperature in degree Celsuis in each of the following situations
Consider the mechanism of a reaction betwwen trans-stilbene and bromine. What isomer do you expect to be the reaction product? Explain your answer. Does the outcome of the experiment support your analysis?
A student prepares a weak acid solution by dissolving 0.2500 g HZ to give 100. mL solution. The titration requires 30.0 mL of 0.1025 M NaOH
The specific heat of mercury metal is 0.138J/gK. How much heat, in joules, is required to heat a 71.5 gram sample of mercury from -6oC to 54.4oC? Enter your answer in scientific notation with no units.
Uric acid dissociates as shown in the figure at the right with a pKa of 5.80, and can be treated as a simple monoprotic acid in this pH range. Its solubility in urine depends on the relative amount of protonated and unprotonated forms. A urine sam..
pH = log[H3O+] , pH + pOH = 14, [H3O+] * [OH-] = 1.0 X 10^-14, pH = -log(0.001) = 3 Could you show me a few of the steps between line one and two in both of these conclusions?
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