Explain how many grams of amonnia are needed to react

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Reference no: EM13528454

Cistaplatin (Pt(NH3)2Cl) is a common Chemotherapeutic agent and is prepared by reacting ammnia with potassium tetrachloride: K2PtCl4+NH+KCL+Pt(NH3)2Cl2. How many grams of amonnia are needed to react with 50.0 grams of potassium tetrachloroplatinate then calculate how many grams of cisplatin are formed from 50.0gm of potassium tetrachloroplatinate, if percent yield for the reaction is 75%.

Reference no: EM13528454

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