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Describe the variational principle. Explain how itprovides the foundation for most modern quantum mechanicalcalculations of chemical importantce. How is it that advances incomputer memory and processor speeds have made it possible to getuseful approximate solutions to system big enough to be of interestin Chemistry?
Given the following thermochemical equations, C2H2(g) + 5/2 O2(g) -----> 2CO2(g) + H2O(l) enthalpy = -1299.5 kJ
use the factor label method to determine what quantity of 5.00x10 -3 M EDTA would be needed to mtitrate ml of water containing .0124 g of calcium carbonate
Why is acceptable to use a mixture of the alpha and beta anomers of D-(+)-mannose in this reaction? (i.e. why isn't it necessary to use either a pure alpha or the pure beta anomer? 2. What is the role of ferric chloride?
Does a reaction with a delta H of 14kj/mol and a delta S of 150 J/molK at 298K favor reactants or products
suggest another small molecule that like water and ammonia might make a good ligand. remember that ligands are electron pair donors which means that one atom must have a lone pair of electrons on it. draw lewis dot structure of the molecule you th..
If you added the oxidizing agent, chromate, to a solution of phenol, would the phenol be oxidized and would a green Cr3+ solution be formed
1. calculate the heat of vaporization of bromine if bromine has pvap 400 mm at 41.0 c and a normal boiling point of
The next three (3) problems deal with the titration of 331 mL of 0.501 M carbonic acid (H2CO3) (Ka1 = 4.3 x 10-7, Ka2 = 5.6 x 10-11) with 1.5 M KOH.
give two examples of elements or compounds that undergo sublimatiom. we studied the sublimation of elemental iodine
Which of the following substances are largely ionic, and which are covalent. (a) HF (b) HI (C) PbCl2 (d) BBr3 (e) NaOH (f) CH3Li
calculate the difference between the Gibbs free energy and Helmholtz free energy for this reaction at normal temperatures and pressures.
Hydrogen cyanide is prepared from ammonia (NH3) and natural gas (CH4).2 NH3 (g) + 3 O2 (g) + 2 CH4 (g) → 2 HCN (g) + 6 H2O (g)
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