Explain highly radioactive material called polonium sulfate

Reference no: EM13250431

The amount (N = grams) of radioactive material present in a sample as a function of time is given by the following equation, where No is the amount present at t = 0. : N (t) = No e^-kt At Great Basin College, we have a specimen of a highly radioactive material called Polonium Sulfate. It is very radioactive. On March 1st we had 100 grams. On March 1st the next year we had 46.97 grams left. What is the "k" factor for this material in the units of "per second"

a. 5.7 x 10^-7 sec^-1

b. 8.8 x 10^-6 sec^-1

c. 9.2 x 10^-3 sec^-1

d. 7.4 x 10^-5 sec^-1

e. 2.4 x 10^-8 sec^-1

f. 5.5 x 10^-8 sec^-1

Reference no: EM13250431

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