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Heat Capacity explained in this answerGiven the following heat capacity data for 2-propanol, determine the amount of heat required to heat 500 mL of 2-propanol from 0 C to it's boiling point.
T CP[K] [J/(mol*K)]
283.15 153.43
293.15 159.79
293.15 160.37
313.15 171.88
333.15 189.41
333.15 190.25
343.15 198.70
343.15 197.74
the rate constant for the second order -reaction is NOBr(g)------>NO(g)+1/2Br2(g) is 48 L/mol*min at a certian temperture. How long will it take for 90.0% of a .0200M solution of NOBr to decompose
For the reaction 2C6H6 + 15O2 → 3CO2 + 6H2O 30 grams of C6H6 are allowed to react with 79.09 grams of O2.
An electron in an excited state of a hydrogen atom emits two photons in succession, the first at 1817 nm and the second at 97.20 nm, to return to the ground state (n=1).
What is the molality of ethanol in a solution made by dissolving 14.6 g of ethanol, C2H5OH, in 53.6 g of water?
calculate how many mgs of Ca2+ are present in 12.0mL of blood and Determine the percent yield 5.04 grams of H2
H2C2O4(aq), Ka1 = 6.5 x 10-2 and Ka2 = 6.1 x 10-5. Don't forget that Kw = 1 x 10-14. Then Determine K for the reaction
How much heat is absorbed when 5.53 mol of NH4NO3 solid is dissolved in water? (Heat of soluton = 25.7 kJ/mol)
A 12.0g sample of a gas has a volume of 5.25L at 29 degrees celcius and 764mmhg . If 2.7g of the same gas is added to this constant 5.25L volume and the temperature raised to 67 degrees celcius.
A gas at 89.0°C occupies a volume of 0.67 L. At what Celsius temperature will the volume increase to 1.12 L
A 4.05 g sample of a compound containing only C, H, and O was burned completely. The only combustion products were 10.942 g CO2 and 4.476 g H2O. What is the empirical formula of the compound.
Draw the enantiomer of proline which would give rise to the absolute stereochemistry and draw a proposed catalytic cycle for the transformation and how does the catalyst activate the substrate
Find the amount of known substance present in the mixture and determine the mass of calcium carbonate present in original mixture.
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