Explain half cells compare electrode potentials calculated

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For each of the half cells compare electrode potentials calculated from (1) concentration and (2) activity data. a) HCl (0.0200 M), Nacl (0.0300 M)|H2 (i.00 atm), Pt b) Fe(Clo4)2 (0.0111M), Fe(ClO4)3(0.0111M)|Pt

Reference no: EM13247087

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