Explain equilibrium constant expression for the reaction

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The equilibrium constant expression for the reaction 2BrF5(g) Br2(g) + 5F2(g) is A) Kc = [Br2] [F2] / [BrF5] D) Kc = [BrF5]2 / [Br2][F2]5 B) Kc = [Br2] [F2]5 / [BrF5]2 E) Kc = 2[BrF5]2 / ([Br2] × 5[F2]5) C) Kc = [Br2] [F2]2 / [BrF5]5

Reference no: EM13333933

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