Explain conclusion for z statistic and p-value

Reference no: EM13128328

Of the 420 respondents in a Christmas tree market survey, 42% had no children at home and 58% had at least one child at home. The corresponding figures for the most recent census are 48% with no children and 52% with at least one child. Test the null hypothesis that the telephone survey technique has a probability of selecting a household with no children that is equal to the value obtained by the census. Give the z statistic (rounded to two decimal places) and the P-value. What do you conclude?

Reference no: EM13128328

Questions Cloud

Set-up or dismantling costs : Alternatively, SCCC can rent a pre-fabricated building at a cost of $1000 per month with no set-up or dismantling costs. It will benefit SCCC to build the office if it expects the stadium project to exceed.

What are the rates of production of p4 and h2 : 4 PH3(g) -> P4(g) + 6 H2(g) If, in a certain experiment, over a specific time period, 0.0039 mol PH3 is consumed in a 1.8 L container during each second of reaction.

Should hamilton follow his boss directive : The Dotson Company, owner of Bleacher Mall, charges Rich Clothing Store a rental fee of $600 per month plus 5% of yearly profits over $500,000. Matt Rich, the owner of the store, directs his accountant, Ron Hamilton, to increase the estimate of ba..

Theories of individual performance style : Evaluate and make strategic recommendations to improve a workplace case based on your own organizational experience

Explain conclusion for z statistic and p-value : No children that is equal to the value obtained by the census. Give the z statistic (rounded to two decimal places) and the P-value. What do you conclude?

A common and novel problem : answer the following questions: •What is the difference between a common and novel problem? •Create an example of a novel problem.

Problem related to cost of goods : Based upon this information which of the following is most correct:

Best communication channel : As a travel agent, you need to contact hundreds of clients and tell them that an increase in fuel costs will force the cruise line to increase its fees.

Test claim that with a single line waiting times vary less : The waiting times have a standard deviation of 4.9 minutes. Use a 0.025 significance level to test the claim that with a single line, waiting times vary less than with individual lines.

User Account

All Pages