Explain aluminum hydroxide reacts with sulfuric acid

Reference no: EM13487521

Aluminum hydroxide reacts with sulfuric acid as follows: 2 Al(OH)3 (s) + 3H2SO4 (aq) rightarrow Al2(SO4)3 (aq) + 6H2O (l) Which reagent is the limiting reactant when 0.700mol Al(OH)3 and 0.700mol H2SO4 are allowed to react? How many moles of Al2(SO4)3 can form under these conditions? How many moles of the excess reactant remain after the completion of the reaction?

Reference no: EM13487521

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