Explain aluminum hydroxide and sulfuric acid reaction

Reference no: EM13125367

Aluminum hydroxide and sulfuric acid reaction

Aluminum hydroxide reacts with sulfuric acid as follows:

2 Al(OH)3 (s) + 3 H2SO4 (aq) ---> Al2(SO4)3 (aq) + 6 H2O (l)

(a) Which reagent is the limiting reactant when 0.450 mol Al(OH)3 and 0.550 mol H2SO4 are allowed to react? How many moles of the excess reactant remain after the completion of the reaction? Please explain in details.

Reference no: EM13125367

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