Explain acetic acid with 0.100m naoh

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1A) For the reaction: I2(g) + Br2(g)<--->2IBr(g), Kc=8.7E2 at 150 degrees celsius. Suppose that 5.04 moles of each substance is placed in a 2.000L container. Will the number of moles of each substance at equilibrium be higher or lower than 5.04? Explain?

B) If Ka is 1.75E-5 for acetic acid, calculate the pH at one-half the equivalence point and at the equivalence point for a titration of 50ml of 0.100M acetic acid with 0.100M NaOH?

Reference no: EM13541600

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